Quote:
Originally Posted by LadyShea
Quote:
Originally Posted by peacegirl
Quote:
Originally Posted by LadyShea
Quote:
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Originally Posted by peacegirl
...if the Sun is bright enough to see it, the photons would be at the retina. The distance between the actual object and the eye is not significant. What is significant is the size and brightness of the object, which allows a mirror image to show up no matter how far away an object is.
it automatically places photons at the retina as a mirror image which means we are in the Sun's optical range due to light, but the light does not have to travel 93 million miles, which is where you are stuck.
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Light doesn't work that way, that's why we keep asking you the same questions over and over.
That distance exists in physics and is significant in physical laws. You must account for light somehow bypassing that distance in your model. |
LadyShea, you are failing to grasp this model which does not change the properties of light. But it does change what light does. If we see in real time, light does not bring the past to us through space/time; it reveals the world to us in real time. There is no bypassing distance in this model. It closes the distance gap because in this model distance is insignificant as long as the conditions of brightness and size are met. There is no violation of physics whatsoever. |
What light does is part of its properties. Distance exists in physics and is significant in physical laws. Distance cannot be closed or negated by brightness or eyes looking.
If you have light physically being somewhere (on the surface of camera film or on the retina) you have to account for it coming to be there by some physical process, otherwise yes, you are violating physics |
You keep talking about "coming to be there". There is no coming to be there in this account because that would require travel and time. But what you're not getting is that the eyes are using light as a condition. These non-absorbed photons are not traveling, even though the full spectrum is traveling. Anything the full spectrum strikes will produce non-absorbed photons which reveal the object, but this split spectrum does not bounce. It disperses and when this occurs there is only white light left. There is no collection of light that will produce an image when the object is no longer present where it can be seen by the naked eye or a telescope.